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Generating Random Passwords with ASP.NET and VB (0 Comments)
Admin: Posted Date: April 4, 2010

This tutorial shows how we can use C# to generate a random password. VB version.Generating random passwords can increase the security of a website by taking the process out of the hands of the user, or simply providing an alternative.

Generating Random Passwords with ASP.NET and VB

This tutorial shows how we can use C# to generate a random password. VB version.

Generating random passwords can increase the security of a website by taking the process out of the hands of the user, or simply providing an alternative, and thus reducing the chance of easily-guessable passwords being used. This tutorial shows a simple method of creating a random password.

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First, we create the ASPX page:

Enter Required Password Length:





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The simple method is shown below. This is how the code-behind should look:


 

Imports Microsoft.VisualBasic
Imports System
Imports System.Data
Imports System.Configuration
Imports System.Web
Imports System.Web.Security
Imports System.Web.UI
Imports System.Web.UI.WebControls
Imports System.Web.UI.WebControls.WebParts
Imports System.Web.UI.HtmlControls

Partial Public Class _Default
Inherits System.Web.UI.Page
Protected Sub Page_Load(ByVal sender As Object, ByVal e As EventArgs)
If IsPostBack Then
Label1.Text = "Please enter a password length (e.g. 8)"
End If
End Sub

Public Shared Function CreateRandomPassword(ByVal PasswordLength As Integer) As String
Dim _allowedChars As String = "abcdefghijkmnopqrstuvwxyzABCDEFGHJKLMNOPQRSTUVWXYZ0123456789"
Dim randNum As New Random()
Dim chars(PasswordLength - 1) As Char
Dim allowedCharCount As Integer = _allowedChars.Length

For i As Integer = 0 To PasswordLength - 1
chars(i) = _allowedChars.Chars(CInt(Fix((_allowedChars.Length) * randNum.NextDouble())))
Next i

Return New String(chars)
End Function

Protected Sub Button1_Click(ByVal sender As Object, ByVal e As EventArgs)
If TextBox1.Text <> "" Then
Dim myInt As String = TextBox1.Text.ToString()
Label1.Text = "Your generated password is: " & CreateRandomPassword(Integer.Parse(myInt))
End If
End Sub
End Class

 

 

 
 
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